Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - Test - Page 650: 7

Answer

(a) $\frac{4}{3}\ rad.$ (b) $15,000\ cm^2$

Work Step by Step

(a) Use $s=r\cdot \theta$ with $s=200\ cm$ and $r=150\ cm$, we have $\theta=\frac{s}{r}=\frac{200}{150}=\frac{4}{3}\ rad.$ (b) The area of the sector is given by $A=\frac{1}{2}r^2\theta=\frac{1}{2}(150)^2(\frac{4}{3})=15,000\ cm^2$
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