Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - Test - Page 650: 14

Answer

$0$

Work Step by Step

As $\frac{3\pi}{2}$ is along the $-y$ axis, we have $cos(\frac{3\pi}{2})=0$
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