Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - Test - Page 650: 1

Answer

$\frac{2\pi}{3}\ rad.$

Work Step by Step

Use the conversion $1^\circ = \frac{\pi}{180}\ rad$, we have $120^\circ =120\times \frac{\pi}{180}=\frac{2\pi}{3}\ rad.$
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