Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Quiz - Page 537: 18

Answer

$-1.181763$

Work Step by Step

Use a scientific calculator and set the unit as $DEG$ for degrees, we have $sec(-212^\circ12')=sec(212^\circ12')=sec(212+\frac{12}{60})^\circ=sec(212.2^\circ)=\frac{1}{cos(212.2^\circ)}=-\frac{1}{cos(32.2^\circ)}\approx-1.181763$
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