Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Quiz - Page 537: 12

Answer

1. $sin135^\circ= \frac{\sqrt 2}{2}$ 2. $cos135^\circ= -\frac{\sqrt 2}{2}$ 3. $tan135^\circ= -1$ 4. $cot135^\circ= -1$ 5. $sec135^\circ= -\sqrt 2$ 6. $csc135^\circ =\sqrt 2$

Work Step by Step

For $135^\circ$, it is in quadrant II with reference angle $\theta=180^\circ-135^\circ=45^\circ$, we have: 1. $sin135^\circ=sin45^\circ=\frac{\sqrt 2}{2}$ 2. $cos135^\circ=-cos45^\circ=-\frac{\sqrt 2}{2}$ 3. $tan135^\circ=-tan45^\circ=-1$ 4. $cot135^\circ=-cot45^\circ=-1$ 5. $sec135^\circ=-sec45^\circ=-\frac{1}{cos45^\circ}=-\sqrt 2$ 6. $csc135^\circ=csc45^\circ=\frac{1}{sin45^\circ}=\sqrt 2$
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