Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Quiz - Page 537: 14

Answer

1. $sin1020^\circ= -\frac{\sqrt 3}{2}$ 2. $cos1020^\circ= \frac{1}{2}$ 3. $tan1020^\circ= -\sqrt 3$ 4. $cot1020^\circ= -\frac{\sqrt 3}{3}$ 5. $sec1020^\circ= 2$ 6. $csc1020^\circ= -\frac{2\sqrt 3}{3}$

Work Step by Step

For $1020^\circ=720^\circ+300^\circ$, it is in quadrant IV with reference angle $\theta=360^\circ-300^\circ=60^\circ$, we have: 1. $sin1020^\circ=-sin60^\circ=-\frac{\sqrt 3}{2}$ 2. $cos1020^\circ=cos60^\circ=\frac{1}{2}$ 3. $tan1020^\circ=-tan60^\circ=-\sqrt 3$ 4. $cot1020^\circ=-cot60^\circ=-\frac{\sqrt 3}{3}$ 5. $sec1020^\circ=sec60^\circ=\frac{1}{cos60^\circ}=2$ 6. $csc1020^\circ=-csc60^\circ=-\frac{1}{sin60^\circ}=-\frac{2\sqrt 3}{3}$
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