Answer
$B= 50.28^\circ$, $a= 32.38\ m$, and $c= 50.66\ m$
Work Step by Step
Given $A=39.72^\circ, b=38.97\ m$, we have $B=90^\circ-39.72^\circ=50.28^\circ$, $a=b\ tanA=38.97\ tan39.72^\circ\approx32.38\ m$, and $c=\frac{b}{cosA}=\frac{38.97}{cos39.72^\circ}\approx50.66\ m$
