Answer
$B= 31^\circ30'$, $a= 638$, and $b= 391$
Work Step by Step
Use the figure given in the exercise, we have $B=90^\circ-58^\circ30'=31^\circ30'$, $a=c\ sinA=748sin(58^\circ30')\approx638$, and $b=c\ cosA=748cos(58^\circ30')\approx391$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - Chapter 5 Test Prep - Review Exercises - Page 561: 59
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