Answer
$A= 19^\circ25'$, $B= 70^\circ35'$, and $c= 390.3$
Work Step by Step
Use the figure given in the exercise, we have $tanA=\frac{a}{b}$, thus $A=tanA(\frac{129.7}{368.1})\approx19^\circ25'$, $B=90^\circ-19^\circ25'=70^\circ35'$, and $c=\sqrt {a^2+b^2}\approx390.3$
