Answer
$\sin A=\frac{k}{z}$
$\cos A=\frac{y}{z}$
$\tan A=\frac{k}{y}$
Work Step by Step
$\sin A=\frac{\text{side opposite}}{\text{hypotenuse}}=\frac{k}{z}$
$\cos A=\frac{\text{side adjacent}}{\text{hypotenuse}}=\frac{y}{z}$
$\tan A=\frac{\text{side opposite}}{\text{side adjacent}}=\frac{k}{y}$
