Answer
$\sin A=\frac{45}{53}$
$\cos A=\frac{28}{53}$
$\tan A=\frac{45}{28}$
Work Step by Step
$\sin A=\frac{\text{side opposite}}{\text{hypotenuse}}=\frac{45}{53}$
$\cos A=\frac{\text{side adjacent}}{\text{hypotenuse}}=\frac{28}{53}$
$\tan A=\frac{\text{side opposite}}{\text{side adjacent}}=\frac{45}{28}$