Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 138: 56

Answer

$[-4, 2)$

Work Step by Step

The idea is to isolate $x$ in the middle. Adding, subtracting or multiplying/dividing with a positive number preserves order (the inequality symbols remain). Multiplying/dividing with a negative number inverts the order (the inequality symbols changes). --- $-6\displaystyle \leq\frac{1}{2}x-4 \lt -3 \qquad $ ... all parts $\times 2$ $-12\leq x-8 \lt -6 \qquad $ ... add $8$ to all parts $-4 \leq x \lt 2 $ ... left border included, right border excluded The solution set is $[-4, 2)$ .
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