Answer
The solution set is $[2, \infty)$
Work Step by Step
The idea is to isolate x on one side.
Adding, subtracting or multiplying/dividing with a positive number preserves order (the inequality symbol remains).
Multiplying/dividing with a negative number inverts the order (the inequality symbol changes)
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$ 8x-2 \geq 14\qquad $ ... $/+2$
$ 8x \geq 16 \qquad $ ... $/\div 8$, (positive)
$ x \geq 2$
The solution set is $[2, \infty)$
