Answer
domain $(-\infty,-2]$, range $(-\infty, \infty)$, not a function.
Work Step by Step
Step 1. Rewriting the equation as $(y-1)^2=-\frac{1}{3}(x+2)$, we see that the parabola opens to the left with a vertex at $(-2,1)$.
Step 2. We can find the domain as $(-\infty,-2]$ and range as $(-\infty, \infty)$
Step 3. The relation is not a function as it will fail a vertical line test.
