Answer
vertex $(-1,-3)$, focus $(2,-3)$, directrix $x=-4$, see graph.
Work Step by Step
Step 1. Given $(y+3)^2=12(x+1)$, we have $4p=12$ and $p=3$ with the parabola opening to the right and vertex $(-1,-3)$.
Step 2. We can find the focus at $(2,-3)$ and directrix as $x=-4$
Step 3. We can graph the parabola as shown in the figure.
