Answer
vertex $(-2,-4)$, focus $(1,-4)$, directrix $x=-5$, see graph.
Work Step by Step
Step 1. Given $(y+4)^2=12(x+2)$, we have $4p=12$ and $p=3$ with the parabola opening to the right and vertex $(-2,-4)$.
Step 2. We can find the focus at $(1,-4)$ and directrix as $x=-5$
Step 3. We can graph the parabola as shown in the figure.
