Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 981: 8

$\dfrac{x^2}{25}-\dfrac{y^2}{24}=1$

Foci: $(-7,0), (7,0)$ and Vertices: $(-5,0)$ and $(5,0)$ We are given that $ c=7; a=5$` Since $ c^2=a^2+b^2$ so, $ b^2=c^2-a^2=49-25=24$ Thus, the equation for the hyperbola is: $\dfrac{x^2}{25}-\dfrac{y^2}{24}=1$