Answer
Asymptotoes : $ y =\pm \dfrac{5}{3} x $
Foci: $(\sqrt {34},0)$, $(-\sqrt {34},0)$
Work Step by Step
The given equation is in the form of $\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$
This implies that $a^2 =9$ and $b^2=25$
and the vertices are: $(-3,0), (3,0)$
The, we have the asymptotes:
$ y =\pm \dfrac{b}{a} x \implies y =\pm \dfrac{5}{3} x $
$ c^2=a^2+b^2 \implies c =\sqrt {34} \approx 5.83$
Hence, our result is:
Asymptotoes : $ y =\pm \dfrac{5}{3} x $
Foci: $(\sqrt {34},0)$, $(-\sqrt {34},0)$
