Answer
See graph and explanations.
Work Step by Step
Step 1. Graph the equation as shown in the figure.
Step 2. We can identify from the given equation that $a=3, b=1$; thus $c=\sqrt {3^2+1^2}=\sqrt {10}$
Step 3. As the center of the ellipse is at $(0,0)$ and the major axis is vertical, the foci are $(0, \pm\sqrt {10})$ and the asymptotes are $y=\pm \frac{3}{1}x=\pm3x$ as shown in the figure.
