Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Mid-Chapter Check Point - Page 1000: 32

Answer

$34.64\ cm$

Work Step by Step

Step 1. Based on the given information, we have $a=\frac{40}{2}=20, b=\frac{20}{2}=10$ Thus $c=\sqrt {a^2-b^2}=10\sqrt 3$ Step 2. The electrode is at the other focus; thus the distance between the electrode and the kidney stone is $2c=20\sqrt 3\approx34.64\ cm$
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