Answer
$-\frac{(x)^2}{5}+\frac{(y)^2}{4}=1$
Work Step by Step
Step 1. From the given conditions, we have $c=3, a=2$ with a vertical major axis; thus $b^2=3^2-2^2=5$
Step 2. The center is at $(0,0)$; thus we can write the equation as $-\frac{(x)^2}{5}+\frac{(y)^2}{4}=1$
