Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.3 - Partial Fractions - Exercise Set - Page 842: 70

Answer

The solution of the equations is $\left( 2.5,-2 \right)$.

Work Step by Step

Let us consider the equation: $4x+3y=4$ …… (I) $y=2x-7$ …… (II) Substitute the value of y from equation (II) in equation (I) so that: $\begin{align} & 4x+3\left( 2x-7 \right)=4 \\ & 4x+6x-21=4 \\ & 10x=4+21 \\ & 10x=25 \end{align}$ Further simplify, $\begin{align} & x=\frac{25}{10} \\ & x=2.5 \end{align}$ Now, put the value of x in equation (II) so that: $\begin{align} & y=2\times 2.5-7 \\ & y=5-7 \\ & y=-2 \\ & x=2.5 \\ \end{align}$ After that, simplify, $y=-2$ Thus, the values are: $x=2.5\text{ and }y=-2$.
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