Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.7 - The Dot Product - Exercise Set - Page 794: 90

Answer

a) Yes, the point $\left( 4,-1 \right)$ satisfies the equation $x+2y=2$. b) Yes, the point $\left( 4,-1 \right)$ satisfies the equation $x-2y=6$.

Work Step by Step

(a). Consider the point $\left( 4,-1 \right)$ as $\left( x,y \right)$. Now put $x=4$ and $y=-1$ to satisfy the equation $x+2y=2$. $\begin{align} & x+2y=2 \\ & 4+2\left( -1 \right)=2 \\ & 4-2=2 \\ & 2=2 \end{align}$ Hence, the $\left( 4,-1 \right)$ satisfies $x+2y=2$. (b). Consider the point $\left( 4,-1 \right)$ as $\left( x,y \right)$. Now put $x=4$ and $y=-1$ to satisfy the equation $x-2y=6$. $\begin{align} & x-2y=6 \\ & 4-2\left( -1 \right)=6 \\ & 4+2=6 \\ & 6=6 \end{align}$ Hence, the $\left( 4,-1 \right)$ satisfies $x-2y=6$.
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