Answer
$\left( 15,\frac{4\pi }{3} \right)$
Work Step by Step
Since it is given that the horse is in the outer circle, therefore r will be calculated as below:
$\begin{align}
& r=6+3+3+3 \\
& =15
\end{align}$
The horse is $\frac{2}{3}$ of the way around the merry-go-round, therefore, the angle intercepted by the horse is given by:
$2\pi \times \frac{2}{3}=\frac{4\pi }{3}$
