Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Mid-Chapter Check Point - Page 756: 19

Answer

The required equation in the polar form is $r=-7\,\csc \,\theta $.

Work Step by Step

We know that $x=r\,\cos \,\theta \ \text{ and }\ y=r\,\sin \,\theta $. Put $x=r\,\cos \,\theta \ \text{ and }\ y=r\,\sin \,\theta $ in the provided equation $y=-7.$ Therefore, $\begin{align} & y=-7 \\ & r\,\sin \,\theta =-7 \\ & r=-7\times \frac{1}{\sin \,\theta } \end{align}$ That is, $r=-7\,\csc \,\theta $.
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