Answer
The graphs appear to coincide.
Work Step by Step
Please note that$$\sin ^2x= \frac{1-\cos 2x}{2}.$$So we have$$3-6\sin ^2x=3-6(\frac{1-\cos 2x}{2})=3\cos 2x.$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 5 - Section 5.3 - Double-Angle, Power-Reducing, and Half-Angle Formulas - Exercise Set - Page 682: 95
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