Answer
Amplitude $=5$ ; $ f=\dfrac{1}{3}$ and Period $=3$
Work Step by Step
Amplitude, $|A|=|-5|=5$
Given: $\omega =\dfrac{2 \pi}{3}$
So, $ f=\dfrac{\omega}{2 \pi}=\dfrac{2\pi/3}{2 \pi}=\dfrac{1}{3}$
Now, period, $ P=\dfrac{2 \pi}{\omega}=\dfrac{2 \pi}{2\pi/3}=3$
Hence, Amplitude $=5$ ; $ f=\dfrac{1}{3}$ and Period $=3$
