Answer
Amplitude $=10$ ; $ f=1$ and Period $=1$
Work Step by Step
Amplitude, $|A|=|10|=10$
Given: $\omega =2 \pi $ and $ f=\dfrac{\omega}{2 \pi}$
So, $ f=\dfrac{\omega}{2 \pi}=\dfrac{2 \pi}{2 \pi}=1$
Now, period, $ P=\dfrac{2 \pi}{\omega}=\dfrac{2 \pi}{2 \pi}=1$
Hence, Amplitude $=10$ ; $ f=1$ and Period $=1$
