Answer
Amplitude $=\dfrac{1}{3}$ ; $ f=\dfrac{1}{\pi}$ and Period $=\pi $
Work Step by Step
Amplitude, $|A|=|\dfrac{1}{3}|=\dfrac{1}{3}$
Given: $\omega =2$
So, $ f=\dfrac{\omega}{2 \pi}=\dfrac{2}{2 \pi}=\dfrac{1}{\pi}$
Now, period, $ P=\dfrac{2 \pi}{\omega}=\dfrac{2 \pi}{2}=\pi $
Hence, Amplitude $=\dfrac{1}{3}$ ; $ f=\dfrac{1}{\pi}$ and Period $=\pi $
