Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.5 - Graphs of Sine and Cosine Functions - Exercise Set - Page 596: 63

Answer

$$y=-2 \sin 2x$$

Work Step by Step

Looking at the graph, we find that this is the reflected graph of a sine function about the $x$-axis with amplitude $2$ and period $\pi$. So, we conclude that $$A=2, \quad B=\frac{2\pi }{\pi }=2 \\ \Rightarrow \quad y=-A \sin Bx = -2 \sin 2x.$$
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