Answer
$\dfrac{2\sqrt 3-1}{2}$
Work Step by Step
Since, $\sin \dfrac{\pi}{3}=\dfrac{\sqrt 3}{2}$
Now, we have
$ f(\dfrac{\pi}{3})= 2 \sin \dfrac{\pi}{3}-\sin ( \dfrac{\dfrac{\pi}{3}}{2}) $
or, $=\dfrac{2\sqrt 3}{2}-\dfrac{1}{2}$
After simplification, we have
or, $=\dfrac{2\sqrt 3-1}{2}$
