Answer
$1$
Work Step by Step
Solve. $\csc 37^{\circ} \sec 53^{\circ}-\tan 53^{\circ} \cot 37^{\circ}$
We have
$= \sec (90^{\circ}-37^{\circ}) \sec 53^{\circ}-\tan 53^{\circ} \tan 53^{\circ}$
or, $=\sec^2 53^{\circ}-\tan^2 53^{\circ}$
Since, $1+\tan^2 x=\sec^2 x $
So, the answer is :
$=1$
