Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.5 - Exponential Growth and Decay; Modeling Data - Exercise Set - Page 505: 1

Answer

$127.3$ million.

Work Step by Step

The mathematical model for exponential growth or decay is given by $ f(t)= A_{0}e^{kt}$ or $ A= A_{0}e^{kt}$. If $ k \gt 0$, the function models the amount of a growing entity. $ A_{0}$ is the original amount, or size, of the growing entity at time t = 0, $ A $ is the amount at time $ t $, and $ k $ is a constant representing the growth rate. If k $ \lt $ 0, the function models the amount of a decaying entity ---- In 2010, the time passed, t=0 (t = years after 2010), and $ A_{0}$ for the given model $\quad A=127.3e^{-0.006t}$ equals $127.3$ million.
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