Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 466: 148

Answer

$$m$$

Work Step by Step

For $f(x)=mx+b$ and $h \neq 0$ we have$$\frac{f(x+h)-f(x)}{h}=\frac{m(x+h)+b-(mx+b)}{h}=\frac{mx+mh+b-mx-b}{h}=\frac{mh}{h}=m$$
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