Answer
False.
$$\frac{\log_28}{\log_24}=\frac{3}{2}$$
Work Step by Step
As we know, $\log_ab^c=c\log_ab$. So we have$$\log_24=\log_22^2=2\log_22=2(1)=2 \\ \log_28=\log_22^3=3\log_22=3(1)=3$$Thus,$$\frac{\log_28}{\log_24}=\frac{3}{2}$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 466: 139
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