Answer
a. $x=-2$, odd multiplicity, $x=-1$, even multiplicity, $x=1$, odd multiplicity,
b. $y=(x+2)(x+1)^2(x-1)^3$
c. $y=-2$
Work Step by Step
a. zeros: $x=-2$, odd multiplicity, $x=-1$, even multiplicity, $x=1$, odd multiplicity,
b. We can write the equation as $y=(x+2)(x+1)^2(x-1)^3$
c. The y-intercept can be found as $y=-2$ by letting $x=0$, or by reading from the given graph.
