Answer
a. $x=-2$, even multiplicity, $x=-1$, odd multiplicity, $x=1$, odd multiplicity
b. $y=(x+2)^2(x+1)(x-1)^3$
c. $y=-4$
Work Step by Step
a. zeros: $x=-2$, even multiplicity, $x=-1$, odd multiplicity, $x=1$, odd multiplicity
b. We can write the equation as $y=(x+2)^2(x+1)(x-1)^3$
c. The y-intercept can be found as $y=-4$ from the above equation by letting $x=0$, or by reading from the given graph.
