Answer
$g(x)=(x+1)^2 + 1$
Work Step by Step
The vertex is $(-1,1)$.
Therefore the function is
$g(x)=(x+1)^2 + 1$.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 2 - Section 2.2 - Quadratic Functions - Exercise Set - Page 330: 2
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