Answer
The required parabola is shown below:
Work Step by Step
Use the steps shown below to determine the graph of the quadratic equation.
Step 1:
The quadratic function can be written as $f\left( x \right)=a{{\left( x-h \right)}^{2}}+k$ corresponding to which the graph is a parabola whose vertex is at $\left( h,k \right)$. Thus, the vertex of the parabola $f\left( x \right)={{\left( x-1 \right)}^{2}}-2$ is $\left( h,k \right)=\left( 1,-2 \right)$.
Step 2:
The standard parabola is also symmetric with respect to the line $x=h$. So, the provided parabola is symmetric to $x=1$.
Step 3:
If $a>0$ , the parabola opens upward and if $a<0$ then the parabola opens downward. Also, if $\left| a \right|$ is small, the parabola opens more flatly than if $\left| a \right|$ is large.
And, from the provided equation of the function, it is observed that the graph opens upwards $a>0$.
Step 4:
So, we see that the above steps lead to the parabola that is open upwards, has a vertex at $\left( 1,-2 \right)$ and intercepts as $\left( \sqrt{2}+1,0 \right)\text{,}\left( -\sqrt{2}+1,0 \right)\text{ and }\left( 0,-1 \right)$. Therefore, the required parabola is shown above.
