Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Review Exercises - Page 429: 10

Answer

The standard form of the expression $\frac{4+\sqrt{-8}}{2}$ is $2+i\sqrt{2}$.

Work Step by Step

Consider the expression, $\frac{4+\sqrt{-8}}{2}$ Rewrite the expression $\frac{4+\sqrt{-8}}{2}$ as $\frac{4+\sqrt{8}\sqrt{-1}}{2}$ As $\sqrt{-1}=i$ Therefore, $\frac{4+\sqrt{8}\sqrt{-1}}{2}=\frac{4+2i\sqrt{2}}{2}$ Simplify the above expression. $\begin{align} & \frac{4+2i\sqrt{2}}{2}=\frac{2\left( 2+i\sqrt{2} \right)}{2} \\ & =2+i\sqrt{2} \end{align}$ Hence, the standard form of the expression $\frac{4+\sqrt{-8}}{2}$ is $2+i\sqrt{2}$.
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