Answer
$\dfrac{-10}{x^2}$
Work Step by Step
$ f^{,}(x)=\dfrac{df(x)}{dx}=10 \dfrac{d(x^{-1})}{dx}$
Since, $ \dfrac{d(x^{-1})}{dx}=(-1) x^{-2} = \dfrac{-1}{x^2}$
So, $ f^{,}(x)=\dfrac{-10}{x^2}$
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