Answer
$2x-5$
Work Step by Step
$ f^{,}(x)=\dfrac{df(x)}{dx}=\dfrac{d(x^{2})}{dx}-5 \dfrac{dx}{dx}+\dfrac{d(1)}{dx}$
Since, $ \dfrac{d(x^{2})}{dx}=2x; \dfrac{dx}{dx}=1$ and $\dfrac{d(1)}{dx}=0$
So, $ f^{,}(x)=2x-5+0=2x-5$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 11 - Test - Page 1180: 13
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