Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Test - Page 1180: 10

Answer

$\dfrac{1}{6}$

Work Step by Step

Recall that if $ f $ is a polynomial function, then we have $\lim_\limits{x\to a}f(x)=f(a)$. In order to to find the limit, we will plug $ a $ into the function and then simplify. $\lim_\limits {x \to 9} \dfrac{\sqrt x-3}{x-9}=\lim_\limits {x \to 9} \dfrac{\sqrt x-3}{(\sqrt x-3)(\sqrt x+3)}$ or, $\lim_\limits {x \to -1} \dfrac{1}{\sqrt x+3}$ or, $=\dfrac{1}{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.