Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.4 - Introduction to Derrivatives - Exercise Set - Page 1175: 53

Answer

The instantaneous rate of change of a function is obtained by taking limit $h\to 0$ in the average rate of change of a function.

Work Step by Step

The average rate of change of a function from $x=a\text{ to }x=a+h$ is given by $\frac{f\left( a+h \right)-f\left( a \right)}{h}$. This is, the slope of the secant line between $\left( a,f\left( a \right) \right)\text{ and }\left( a+h,f\left( a+h \right) \right)$. The instantaneous rate of change of a function at a point $\left( a,f\left( a \right) \right)$ is given by $\underset{h\to 0}{\mathop{\lim }}\,\frac{f\left( a+h \right)-f\left( a \right)}{h}$. This is the slope of the tangent line at $\left( a,f\left( a \right) \right)$. Thus, the instantaneous rate of change of a function is obtained by taking limit $h\to 0$ in the average rate of change of a function.
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