Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.3 - Limits and Continuity - Exercise Set - Page 1162: 49

Answer

The function at the point $ a $ shows a ‘jump’ and ‘hole’ in the graph, if it is defined at that point $ a $, $\ \underset{x\to a}{\mathop{\lim }}\,f\left( x \right)$ exists but $\ \underset{x\to a}{\mathop{\lim }}\,f\left( x \right)\ne f\left( a \right)$.

Work Step by Step

Since $\ \underset{x\to a}{\mathop{\lim }}\,f\left( x \right)$ exists but $\ \underset{x\to a}{\mathop{\lim }}\,f\left( x \right)\ne f\left( a \right)$, so the function cannot be continuous at the point a. The graph of such functions shows a ‘jump’ and ‘hole’ at that point $ a $.
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