Answer
$8019$
Work Step by Step
The sum of an arithmetic sequence is given by: $S_n=\dfrac{n}{2}[a_1+a_n]$ and the nth term for an arithmetic sequence is given by $a_n=a_1+(n-1) d$
We are given that $11,33, 99, 297,......$
This gives: $a_n=a_1 \cdot 3^{n-1} $
Here, $a_7=11 \cdot 3^{7-1} =11 \cdot 3^{6}$
Hence, $a_7=8019$
