Answer
$320$ Degree days
Work Step by Step
The sum of an arithmetic sequence is given by: $S_n=\dfrac{n}{2}[a_1+a_n]$ and the nth term for an arithmetic sequence is given by $a_n=a_1+(n-1) d$
We are given that $a_n= 314, 628$
Now, $a_{10}=23+(10-1) \times 2=41$
The sum of an arithmetic sequence is given by: $S_n=\dfrac{n}{2}[a_1+a_n]$
$S_{10}=\dfrac{10}{2}[23+41]=320$ Degree- days