Answer
$2869$ Seats
Work Step by Step
We know that $a_n=a_1+(n-1) d$
Here, we have $a_1=20$ and $d=3$
and $a_{38}=20+3(38-1)=131$
The sum of an arithmetic sequence is given by: $S_n=\dfrac{n}{2}[a_1+a_n]$
$S_{38}=\dfrac{38}{2}[20+131]=2869$ Seats