Answer
The sum of the series is, $\sum\limits_{i=1}^{6}{5i}=105,\sum\limits_{i=1}^{6}{7i}=147,\sum\limits_{i=1}^{4}{2{{i}^{2}}}=60,\sum\limits_{i=1}^{5}{{{i}^{3}}}=225$ and
$\sum\limits_{k=1}^{5}{k\left( k+4 \right)}=115$.
Work Step by Step
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