Answer
At the end of the year, the value of the car is $\dfrac{3}{4}$ of the value of the previous year.
Work Step by Step
Here, we have $a_5=25,000 (\dfrac{3}{4})^5 \approx 5933$
and
$a_{n+1}=25,000 (\dfrac{3}{4})^{n+1}$
or, $a_{n+1}=25,000 (\dfrac{3}{4})^{n} \cdot (3/4) \approx 5933$
Thus, $a_{n+1}=a_n (\dfrac{3}{4})$
This implies that at the end of the year the value of the car is $\dfrac{3}{4}$ of the value of the previous year.
